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100224115 = 520044823
BaseRepresentation
bin1011111100101…
…00110001110011
320222120220122021
411332110301303
5201124132430
613540052311
72324614405
oct576246163
9228526567
10100224115
1151634952
1229694097
13179c1814
14d44cb75
158beb07a
hex5f94c73

100224115 has 4 divisors (see below), whose sum is σ = 120268944. Its totient is φ = 80179288.

The previous prime is 100224101. The next prime is 100224119. The reversal of 100224115 is 511422001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100224115 - 27 = 100223987 is a prime.

It is a super-3 number, since 3×1002241153 (a number of 25 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100224119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10022407 + ... + 10022416.

It is an arithmetic number, because the mean of its divisors is an integer number (30067236).

Almost surely, 2100224115 is an apocalyptic number.

100224115 is a deficient number, since it is larger than the sum of its proper divisors (20044829).

100224115 is an equidigital number, since it uses as much as digits as its factorization.

100224115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20044828.

The product of its (nonzero) digits is 80, while the sum is 16.

The square root of 100224115 is about 10011.1994785840. The cubic root of 100224115 is about 464.5053745376.

Adding to 100224115 its reverse (511422001), we get a palindrome (611646116).

The spelling of 100224115 in words is "one hundred million, two hundred twenty-four thousand, one hundred fifteen".

Divisors: 1 5 20044823 100224115