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100230011313 = 3171231951177
BaseRepresentation
bin101110101011000101…
…1001001100110110001
3100120201012110010110020
41131112023021212301
53120232340330223
6114013420554053
710145536016265
oct1352613114661
9316635403406
10100230011313
1139564256aa3
12175129b2929
1395b4373c03
144bcb8160a5
1529195211e3
hex17562c99b1

100230011313 has 8 divisors (see below), whose sum is σ = 133647888288. Its totient is φ = 66816070944.

The previous prime is 100230011267. The next prime is 100230011333. The reversal of 100230011313 is 313110032001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100230011313 - 222 = 100225817009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100230011292 and 100230011301.

It is not an unprimeable number, because it can be changed into a prime (100230011333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 924220 + ... + 1026957.

It is an arithmetic number, because the mean of its divisors is an integer number (16705986036).

Almost surely, 2100230011313 is an apocalyptic number.

It is an amenable number.

100230011313 is a deficient number, since it is larger than the sum of its proper divisors (33417876975).

100230011313 is a wasteful number, since it uses less digits than its factorization.

100230011313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1968303.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 100230011313 its reverse (313110032001), we get a palindrome (413340043314).

The spelling of 100230011313 in words is "one hundred billion, two hundred thirty million, eleven thousand, three hundred thirteen".

Divisors: 1 3 17123 51369 1951177 5853531 33410003771 100230011313