1002301300121 has 4 divisors (see below), whose sum is σ = 1093419600144. Its totient is φ = 911183000100.

The previous prime is 1002301300073. The next prime is 1002301300139. The reversal of 1002301300121 is 1210031032001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1002301300121 - 2³⁰ = 1001227558297 is a prime.

It is a super-2 number, since 2×1002301300121² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1002301300096 and 1002301300105.

It is not an unprimeable number, because it can be changed into a prime (1002301350121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45559149995 + ... + 45559150016.

It is an arithmetic number, because the mean of its divisors is an integer number (273354900036).

Almost surely, 2^{1002301300121} is an apocalyptic number.

1002301300121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1002301300121 is a deficient number, since it is larger than the sum of its proper divisors (91118300023).

1002301300121 is an equidigital number, since it uses as much as digits as its factorization.

1002301300121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91118300022.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 1002301300121 its reverse (1210031032001), we get a palindrome (2212332332122).

The spelling of 1002301300121 in words is "one trillion, two billion, three hundred one million, three hundred thousand, one hundred twenty-one".