10023151433 has 4 divisors (see below), whose sum is σ = 10035511248. Its totient is φ = 10010791620.

The previous prime is 10023151421. The next prime is 10023151441. The reversal of 10023151433 is 33415132001.

10023151433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33415132001 = 137 ⋅243906073.

It is a cyclic number.

It is not a de Polignac number, because 10023151433 - 2¹⁴ = 10023135049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10023151399 and 10023151408.

It is not an unprimeable number, because it can be changed into a prime (10023151403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6178691 + ... + 6180312.

It is an arithmetic number, because the mean of its divisors is an integer number (2508877812).

Almost surely, 2^10023151433 is an apocalyptic number.

It is an amenable number.

10023151433 is a deficient number, since it is larger than the sum of its proper divisors (12359815).

10023151433 is an equidigital number, since it uses as much as digits as its factorization.

10023151433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12359814.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 10023151433 its reverse (33415132001), we get a palindrome (43438283434).

The spelling of 10023151433 in words is "ten billion, twenty-three million, one hundred fifty-one thousand, four hundred thirty-three".