100232002113 has 4 divisors (see below), whose sum is σ = 133642669488. Its totient is φ = 66821334740.

The previous prime is 100232002067. The next prime is 100232002141. The reversal of 100232002113 is 311200232001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100232002113 - 2⁹ = 100232001601 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 100232002092 and 100232002101.

It is not an unprimeable number, because it can be changed into a prime (100232002313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16705333683 + ... + 16705333688.

It is an arithmetic number, because the mean of its divisors is an integer number (33410667372).

Almost surely, 2^100232002113 is an apocalyptic number.

It is an amenable number.

100232002113 is a deficient number, since it is larger than the sum of its proper divisors (33410667375).

100232002113 is an equidigital number, since it uses as much as digits as its factorization.

100232002113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33410667374.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 100232002113 its reverse (311200232001), we get a palindrome (411432234114).

The spelling of 100232002113 in words is "one hundred billion, two hundred thirty-two million, two thousand, one hundred thirteen".