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100234335011 = 143969655549
BaseRepresentation
bin101110101011001101…
…1101001001100100011
3100120201111120210110012
41131112123221030203
53120234442210021
6114014053355135
710145620534646
oct1352633511443
9316644523405
10100234335011
113956673a4a8
1217514338aab
1395b5228c05
144bcc21da5d
152919ac735b
hex17566e9323

100234335011 has 4 divisors (see below), whose sum is σ = 100303992000. Its totient is φ = 100164678024.

The previous prime is 100234334983. The next prime is 100234335031. The reversal of 100234335011 is 110533432001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110533432001 = 1061104178541.

It is a cyclic number.

It is not a de Polignac number, because 100234335011 - 210 = 100234333987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100234335031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34826336 + ... + 34829213.

It is an arithmetic number, because the mean of its divisors is an integer number (25075998000).

Almost surely, 2100234335011 is an apocalyptic number.

100234335011 is a deficient number, since it is larger than the sum of its proper divisors (69656989).

100234335011 is an equidigital number, since it uses as much as digits as its factorization.

100234335011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69656988.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 100234335011 its reverse (110533432001), we get a palindrome (210767767012).

The spelling of 100234335011 in words is "one hundred billion, two hundred thirty-four million, three hundred thirty-five thousand, eleven".

Divisors: 1 1439 69655549 100234335011