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100244444435 = 520048888887
BaseRepresentation
bin101110101011100001…
…0001101010100010011
3100120202012121101222022
41131113002031110103
53120300034210220
6114015054202055
710146102501332
oct1352702152423
9316665541868
10100244444435
11395714148a3
12175177b332b
1395b7358515
144bcd6d1d19
15291a922925
hex175708d513

100244444435 has 4 divisors (see below), whose sum is σ = 120293333328. Its totient is φ = 80195555544.

The previous prime is 100244444431. The next prime is 100244444441. The reversal of 100244444435 is 534444442001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100244444435 - 22 = 100244444431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100244444395 and 100244444404.

It is not an unprimeable number, because it can be changed into a prime (100244444431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10024444439 + ... + 10024444448.

It is an arithmetic number, because the mean of its divisors is an integer number (30073333332).

Almost surely, 2100244444435 is an apocalyptic number.

100244444435 is a deficient number, since it is larger than the sum of its proper divisors (20048888893).

100244444435 is an equidigital number, since it uses as much as digits as its factorization.

100244444435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20048888892.

The product of its (nonzero) digits is 122880, while the sum is 35.

Adding to 100244444435 its reverse (534444442001), we get a palindrome (634688886436).

The spelling of 100244444435 in words is "one hundred billion, two hundred forty-four million, four hundred forty-four thousand, four hundred thirty-five".

Divisors: 1 5 20048888887 100244444435