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10025300035 = 53754190811
BaseRepresentation
bin10010101011000110…
…11111000001000011
3221212200101000020201
421111203133001003
5131012434100120
64334444550031
7503302433662
oct112543370103
927780330221
1010025300035
114285025333
121b39552317
13c3a0080ca
146b166add9
153da20940a
hex2558df043

10025300035 has 8 divisors (see below), whose sum is σ = 12355505136. Its totient is φ = 7803476640.

The previous prime is 10025300009. The next prime is 10025300071. The reversal of 10025300035 is 53000352001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10025300035 - 215 = 10025267267 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10025299985 and 10025300021.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27095221 + ... + 27095590.

It is an arithmetic number, because the mean of its divisors is an integer number (1544438142).

Almost surely, 210025300035 is an apocalyptic number.

10025300035 is a deficient number, since it is larger than the sum of its proper divisors (2330205101).

10025300035 is an equidigital number, since it uses as much as digits as its factorization.

10025300035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54190853.

The product of its (nonzero) digits is 450, while the sum is 19.

Adding to 10025300035 its reverse (53000352001), we get a palindrome (63025652036).

The spelling of 10025300035 in words is "ten billion, twenty-five million, three hundred thousand, thirty-five".

Divisors: 1 5 37 185 54190811 270954055 2005060007 10025300035