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100300000041 = 3223484541063
BaseRepresentation
bin101110101101001011…
…0001000101100101001
3100120220002010220221100
41131122112020230221
53120403300000131
6114024401032013
710150345635123
oct1353226105451
9316802126840
10100300000041
113959a80a61a
1217532325609
1395c5a0a567
144bd6c34213
1529207487e6
hex175a588b29

100300000041 has 12 divisors (see below), whose sum is σ = 151176811968. Its totient is φ = 63959420184.

The previous prime is 100300000027. The next prime is 100300000079. The reversal of 100300000041 is 140000003001.

It is not a de Polignac number, because 100300000041 - 27 = 100299999913 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a junction number, because it is equal to n+sod(n) for n = 100299999969 and 100300000032.

It is not an unprimeable number, because it can be changed into a prime (100300000091) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 242270325 + ... + 242270738.

It is an arithmetic number, because the mean of its divisors is an integer number (12598067664).

Almost surely, 2100300000041 is an apocalyptic number.

It is an amenable number.

100300000041 is a deficient number, since it is larger than the sum of its proper divisors (50876811927).

100300000041 is a wasteful number, since it uses less digits than its factorization.

100300000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 484541092 (or 484541089 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 9.

Adding to 100300000041 its reverse (140000003001), we get a palindrome (240300003042).

The spelling of 100300000041 in words is "one hundred billion, three hundred million, forty-one", and thus it is an aban number.

Divisors: 1 3 9 23 69 207 484541063 1453623189 4360869567 11144444449 33433333347 100300000041