Search a number
-
+
100303102003 = 137715623231
BaseRepresentation
bin101110101101010000…
…1111110000000110011
3100120220021222112000211
41131122201332000303
53120410043231003
6114024551324551
710150414204546
oct1353241760063
9316807875024
10100303102003
11395a1539125
1217533380757
1395c6555440
144bd740085d
152920b5c96d
hex175a87e033

100303102003 has 4 divisors (see below), whose sum is σ = 108018725248. Its totient is φ = 92587478760.

The previous prime is 100303101971. The next prime is 100303102019. The reversal of 100303102003 is 300201303001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100303102003 - 25 = 100303101971 is a prime.

It is a super-2 number, since 2×1003031020032 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 7715623231 = 100303102003 / (1 + 0 + 0 + 3 + 0 + 3 + 1 + 0 + 2 + 0 + 0 + 3).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100303102903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3857811603 + ... + 3857811628.

It is an arithmetic number, because the mean of its divisors is an integer number (27004681312).

Almost surely, 2100303102003 is an apocalyptic number.

100303102003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

100303102003 is a deficient number, since it is larger than the sum of its proper divisors (7715623245).

100303102003 is an equidigital number, since it uses as much as digits as its factorization.

100303102003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7715623244.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 100303102003 its reverse (300201303001), we get a palindrome (400504405004).

The spelling of 100303102003 in words is "one hundred billion, three hundred three million, one hundred two thousand, three".

Divisors: 1 13 7715623231 100303102003