Base | Representation |
---|---|
bin | 10110110011101100111110… |
… | …101101100001110000001011 |
3 | 111011011112200022001221001001 |
4 | 112303230332231201300023 |
5 | 101121434401402221303 |
6 | 553201441200035431 |
7 | 30062105432655151 |
oct | 2663547655416013 |
9 | 434145608057031 |
10 | 100310013320203 |
11 | 29a64268496115 |
12 | b300904602b77 |
13 | 43c8269646b9b |
14 | 1aab05db833d1 |
15 | b8e4610bd31d |
hex | 5b3b3eb61c0b |
100310013320203 has 4 divisors (see below), whose sum is σ = 100310036308560. Its totient is φ = 100309990331848.
The previous prime is 100310013320173. The next prime is 100310013320213. The reversal of 100310013320203 is 302023310013001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 100310013320203 - 229 = 100309476449291 is a prime.
It is a super-2 number, since 2×1003100133202032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (100310013320213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2712448 + ... + 14421421.
It is an arithmetic number, because the mean of its divisors is an integer number (25077509077140).
Almost surely, 2100310013320203 is an apocalyptic number.
100310013320203 is a deficient number, since it is larger than the sum of its proper divisors (22988357).
100310013320203 is an equidigital number, since it uses as much as digits as its factorization.
100310013320203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22988356.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 100310013320203 its reverse (302023310013001), we get a palindrome (402333323333204).
The spelling of 100310013320203 in words is "one hundred trillion, three hundred ten billion, thirteen million, three hundred twenty thousand, two hundred three".
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