100310121313003 has 4 divisors (see below), whose sum is σ = 114640138643440. Its totient is φ = 85980103982568.

The previous prime is 100310121312979. The next prime is 100310121313013. The reversal of 100310121313003 is 300313121013001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100310121313003 - 2⁴⁵ = 65125749224171 is a prime.

It is a super-3 number, since 3×100310121313003³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100310121313013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7165008665208 + ... + 7165008665221.

It is an arithmetic number, because the mean of its divisors is an integer number (28660034660860).

Almost surely, 2^{100310121313003} is an apocalyptic number.

100310121313003 is a deficient number, since it is larger than the sum of its proper divisors (14330017330437).

100310121313003 is an equidigital number, since it uses as much as digits as its factorization.

100310121313003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14330017330436.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 100310121313003 its reverse (300313121013001), we get a palindrome (400623242326004).

The spelling of 100310121313003 in words is "one hundred trillion, three hundred ten billion, one hundred twenty-one million, three hundred thirteen thousand, three".