1003112040113 has 4 divisors (see below), whose sum is σ = 1003156103460. Its totient is φ = 1003067976768.

The previous prime is 1003112040109. The next prime is 1003112040131. The reversal of 1003112040113 is 3110402113001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 886972171264 + 116139868849 = 941792^2 + 340793^2 .

It is a cyclic number.

It is not a de Polignac number, because 1003112040113 - 2² = 1003112040109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1003112040091 and 1003112040100.

It is not an unprimeable number, because it can be changed into a prime (1003112040193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21997508 + ... + 22043061.

It is an arithmetic number, because the mean of its divisors is an integer number (250789025865).

Almost surely, 2^{1003112040113} is an apocalyptic number.

It is an amenable number.

1003112040113 is a deficient number, since it is larger than the sum of its proper divisors (44063347).

1003112040113 is an equidigital number, since it uses as much as digits as its factorization.

1003112040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44063346.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1003112040113 its reverse (3110402113001), we get a palindrome (4113514153114).

The spelling of 1003112040113 in words is "one trillion, three billion, one hundred twelve million, forty thousand, one hundred thirteen".