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10031213003 = 71433030429
BaseRepresentation
bin10010101011110100…
…00010100111001011
3221220002111102022112
421111322002213023
5131020442304003
64335215412535
7503403621650
oct112572024713
927802442275
1010031213003
1142883a3889
121b3b52414b
13c3b2c85c6
146b2369c27
153da9c63d8
hex255e829cb

10031213003 has 4 divisors (see below), whose sum is σ = 11464243440. Its totient is φ = 8598182568.

The previous prime is 10031212913. The next prime is 10031213029. The reversal of 10031213003 is 30031213001.

10031213003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10031213003 - 218 = 10030950859 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10031213603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 716515208 + ... + 716515221.

It is an arithmetic number, because the mean of its divisors is an integer number (2866060860).

Almost surely, 210031213003 is an apocalyptic number.

10031213003 is a deficient number, since it is larger than the sum of its proper divisors (1433030437).

10031213003 is an equidigital number, since it uses as much as digits as its factorization.

10031213003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1433030436.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 10031213003 its reverse (30031213001), we get a palindrome (40062426004).

The spelling of 10031213003 in words is "ten billion, thirty-one million, two hundred thirteen thousand, three".

Divisors: 1 7 1433030429 10031213003