100313140243331 has 4 divisors (see below), whose sum is σ = 100313378893200. Its totient is φ = 100312901593464.

The previous prime is 100313140243301. The next prime is 100313140243367. The reversal of 100313140243331 is 133342041313001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100313140243331 - 2³⁸ = 100038262336387 is a prime.

It is a super-2 number, since 2×100313140243331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100313140243294 and 100313140243303.

It is not an unprimeable number, because it can be changed into a prime (100313140243301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118693316 + ... + 119535473.

It is an arithmetic number, because the mean of its divisors is an integer number (25078344723300).

Almost surely, 2^{100313140243331} is an apocalyptic number.

100313140243331 is a deficient number, since it is larger than the sum of its proper divisors (238649869).

100313140243331 is an equidigital number, since it uses as much as digits as its factorization.

100313140243331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 238649868.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 100313140243331 its reverse (133342041313001), we get a palindrome (233655181556332).

The spelling of 100313140243331 in words is "one hundred trillion, three hundred thirteen billion, one hundred forty million, two hundred forty-three thousand, three hundred thirty-one".