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1003141231203 = 3334380410401
BaseRepresentation
bin11101001100011111110…
…00000111001001100011
310112220021122012111121110
432212033320013021203
5112413413123344303
62044500421554403
7132321526530336
oct16461770071143
93486248174543
101003141231203
11357480089441
121424b9b75a03
1373798ccb927
14367a36d461d
151b162406703
hexe98fe07263

1003141231203 has 4 divisors (see below), whose sum is σ = 1337521641608. Its totient is φ = 668760820800.

The previous prime is 1003141231199. The next prime is 1003141231217. The reversal of 1003141231203 is 3021321413001.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1003141231203 - 22 = 1003141231199 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1003141231203.

It is not an unprimeable number, because it can be changed into a prime (1003141231283) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167190205198 + ... + 167190205203.

It is an arithmetic number, because the mean of its divisors is an integer number (334380410402).

Almost surely, 21003141231203 is an apocalyptic number.

1003141231203 is a deficient number, since it is larger than the sum of its proper divisors (334380410405).

1003141231203 is an equidigital number, since it uses as much as digits as its factorization.

1003141231203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 334380410404.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1003141231203 its reverse (3021321413001), we get a palindrome (4024462644204).

The spelling of 1003141231203 in words is "one trillion, three billion, one hundred forty-one million, two hundred thirty-one thousand, two hundred three".

Divisors: 1 3 334380410401 1003141231203