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100314142003 = 170958697567
BaseRepresentation
bin101110101101100110…
…0000101010100110011
3100120221001202102001201
41131123030011110303
53120420410021003
6114030024112031
710150610065255
oct1353314052463
9316831672051
10100314142003
11395a7799699
1217537005617
1395c891c49a
144bd8a75cd5
152921addb1d
hex175b305533

100314142003 has 4 divisors (see below), whose sum is σ = 100372841280. Its totient is φ = 100255442728.

The previous prime is 100314141971. The next prime is 100314142013. The reversal of 100314142003 is 300241413001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100314142003 - 25 = 100314141971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100314142013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29347075 + ... + 29350492.

It is an arithmetic number, because the mean of its divisors is an integer number (25093210320).

Almost surely, 2100314142003 is an apocalyptic number.

100314142003 is a deficient number, since it is larger than the sum of its proper divisors (58699277).

100314142003 is an equidigital number, since it uses as much as digits as its factorization.

100314142003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58699276.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 100314142003 its reverse (300241413001), we get a palindrome (400555555004).

The spelling of 100314142003 in words is "one hundred billion, three hundred fourteen million, one hundred forty-two thousand, three".

Divisors: 1 1709 58697567 100314142003