1003144041131 has 4 divisors (see below), whose sum is σ = 1003209369600. Its totient is φ = 1003078712664.

The previous prime is 1003144041113. The next prime is 1003144041161. The reversal of 1003144041131 is 1311404413001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1003144041131 - 2¹⁴ = 1003144024747 is a prime.

It is a super-2 number, since 2×1003144041131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1003144041097 and 1003144041106.

It is not an unprimeable number, because it can be changed into a prime (1003144041101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32641196 + ... + 32671913.

It is an arithmetic number, because the mean of its divisors is an integer number (250802342400).

Almost surely, 2^{1003144041131} is an apocalyptic number.

1003144041131 is a deficient number, since it is larger than the sum of its proper divisors (65328469).

1003144041131 is an equidigital number, since it uses as much as digits as its factorization.

1003144041131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65328468.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1003144041131 its reverse (1311404413001), we get a palindrome (2314548454132).

The spelling of 1003144041131 in words is "one trillion, three billion, one hundred forty-four million, forty-one thousand, one hundred thirty-one".