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10031474153 = 29393413227
BaseRepresentation
bin10010101011110110…
…00010010111101001
3221220002222200112202
421111323002113221
5131021024133103
64335225145545
7503406060221
oct112573022751
927802880482
1010031474153
114288562008
121b3b62b2b5
13c3b38a42c
146b23d7081
153daa28988
hex255ec25e9

10031474153 has 4 divisors (see below), whose sum is σ = 10034890320. Its totient is φ = 10028057988.

The previous prime is 10031474107. The next prime is 10031474161. The reversal of 10031474153 is 35147413001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35147413001 = 173203164237.

It is a cyclic number.

It is not a de Polignac number, because 10031474153 - 232 = 5736506857 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10031474183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1703675 + ... + 1709552.

It is an arithmetic number, because the mean of its divisors is an integer number (2508722580).

Almost surely, 210031474153 is an apocalyptic number.

It is an amenable number.

10031474153 is a deficient number, since it is larger than the sum of its proper divisors (3416167).

10031474153 is an equidigital number, since it uses as much as digits as its factorization.

10031474153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3416166.

The product of its (nonzero) digits is 5040, while the sum is 29.

Adding to 10031474153 its reverse (35147413001), we get a palindrome (45178887154).

The spelling of 10031474153 in words is "ten billion, thirty-one million, four hundred seventy-four thousand, one hundred fifty-three".

Divisors: 1 2939 3413227 10031474153