100321411121 has 4 divisors (see below), whose sum is σ = 100322125044. Its totient is φ = 100320697200.

The previous prime is 100321411103. The next prime is 100321411133. The reversal of 100321411121 is 121114123001.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 121114123001 = 29 ⋅4176349069.

It can be written as a sum of positive squares in 2 ways, for example, as 27701940721 + 72619470400 = 166439^2 + 269480^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100321411121 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 100321411121.

It is not an unprimeable number, because it can be changed into a prime (100321411921) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68450 + ... + 453131.

It is an arithmetic number, because the mean of its divisors is an integer number (25080531261).

Almost surely, 2^100321411121 is an apocalyptic number.

It is an amenable number.

100321411121 is a deficient number, since it is larger than the sum of its proper divisors (713923).

100321411121 is an equidigital number, since it uses as much as digits as its factorization.

100321411121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 713922.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 100321411121 its reverse (121114123001), we get a palindrome (221435534122).

The spelling of 100321411121 in words is "one hundred billion, three hundred twenty-one million, four hundred eleven thousand, one hundred twenty-one".