10033002113 has 4 divisors (see below), whose sum is σ = 10054672128. Its totient is φ = 10011332100.

The previous prime is 10033002073. The next prime is 10033002151. The reversal of 10033002113 is 31120033001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10033002113 - 2¹⁰ = 10033001089 is a prime.

It is a super-3 number, since 3×10033002113³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10033002713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10834313 + ... + 10835238.

It is an arithmetic number, because the mean of its divisors is an integer number (2513668032).

Almost surely, 2^10033002113 is an apocalyptic number.

It is an amenable number.

10033002113 is a deficient number, since it is larger than the sum of its proper divisors (21670015).

10033002113 is an equidigital number, since it uses as much as digits as its factorization.

10033002113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21670014.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 10033002113 its reverse (31120033001), we get a palindrome (41153035114).

The spelling of 10033002113 in words is "ten billion, thirty-three million, two thousand, one hundred thirteen".