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100330103113 = 103974078671
BaseRepresentation
bin101110101110000100…
…0111110000101001001
3100120222011210022120221
41131130020332011021
53120434001244423
6114031354150041
710151162543152
oct1353410760511
9316864708527
10100330103113
1139605800499
1217540422321
1395cc01a426
144bdac2c929
1529231e2e5d
hex175c23e149

100330103113 has 4 divisors (see below), whose sum is σ = 101304181888. Its totient is φ = 99356024340.

The previous prime is 100330103077. The next prime is 100330103123. The reversal of 100330103113 is 311301033001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100330103113 is a prime.

It is a super-2 number, since 2×1003301031132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100330103123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 487039233 + ... + 487039438.

It is an arithmetic number, because the mean of its divisors is an integer number (25326045472).

Almost surely, 2100330103113 is an apocalyptic number.

It is an amenable number.

100330103113 is a deficient number, since it is larger than the sum of its proper divisors (974078775).

100330103113 is an equidigital number, since it uses as much as digits as its factorization.

100330103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 974078774.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 100330103113 its reverse (311301033001), we get a palindrome (411631136114).

The spelling of 100330103113 in words is "one hundred billion, three hundred thirty million, one hundred three thousand, one hundred thirteen".

Divisors: 1 103 974078671 100330103113