1003312121131 has 4 divisors (see below), whose sum is σ = 1012516819600. Its totient is φ = 994107422664.

The previous prime is 1003312121051. The next prime is 1003312121137. The reversal of 1003312121131 is 1311212133001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1003312121131 - 2¹⁷ = 1003311990059 is a prime.

It is a super-2 number, since 2×1003312121131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1003312121099 and 1003312121108.

It is not an unprimeable number, because it can be changed into a prime (1003312121137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4602349071 + ... + 4602349288.

It is an arithmetic number, because the mean of its divisors is an integer number (253129204900).

Almost surely, 2^{1003312121131} is an apocalyptic number.

1003312121131 is a deficient number, since it is larger than the sum of its proper divisors (9204698469).

1003312121131 is an equidigital number, since it uses as much as digits as its factorization.

1003312121131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9204698468.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1003312121131 its reverse (1311212133001), we get a palindrome (2314524254132).

The spelling of 1003312121131 in words is "one trillion, three billion, three hundred twelve million, one hundred twenty-one thousand, one hundred thirty-one".