Base | Representation |
---|---|
bin | 101110101110001000… |
… | …0101011011111100011 |
3 | 100120222022120222220110 |
4 | 1131130100223133203 |
5 | 3120440010433011 |
6 | 114031505342403 |
7 | 10151215661301 |
oct | 1353420533743 |
9 | 316868528813 |
10 | 100332124131 |
11 | 39606960958 |
12 | 17541037a03 |
13 | 95cc5772b5 |
14 | 4bdb1d7271 |
15 | 2923491ba6 |
hex | 175c42b7e3 |
100332124131 has 8 divisors (see below), whose sum is σ = 133992985104. Its totient is φ = 66779672960.
The previous prime is 100332124129. The next prime is 100332124163. The reversal of 100332124131 is 131421233001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 100332124131 - 21 = 100332124129 is a prime.
It is a super-2 number, since 2×1003321241312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100332124098 and 100332124107.
It is not an unprimeable number, because it can be changed into a prime (100332128131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27100290 + ... + 27103991.
It is an arithmetic number, because the mean of its divisors is an integer number (16749123138).
Almost surely, 2100332124131 is an apocalyptic number.
100332124131 is a deficient number, since it is larger than the sum of its proper divisors (33660860973).
100332124131 is an equidigital number, since it uses as much as digits as its factorization.
100332124131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54204901.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 100332124131 its reverse (131421233001), we get a palindrome (231753357132).
The spelling of 100332124131 in words is "one hundred billion, three hundred thirty-two million, one hundred twenty-four thousand, one hundred thirty-one".
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