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10033302113 = 59935394733
BaseRepresentation
bin10010101100000100…
…00000101001100001
3221220020102120000222
421112002000221201
5131022011131423
64335332252425
7503430442442
oct112602005141
927806376028
1010033302113
1142895a041a
121b40171115
13c3b87a473
146b27512c9
153dac8a3c8
hex256080a61

10033302113 has 8 divisors (see below), whose sum is σ = 10055016000. Its totient is φ = 10011605968.

The previous prime is 10033302091. The next prime is 10033302151. The reversal of 10033302113 is 31120333001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10033302113 - 26 = 10033302049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10033302091 and 10033302100.

It is not an unprimeable number, because it can be changed into a prime (10033302313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2117495 + ... + 2122227.

It is an arithmetic number, because the mean of its divisors is an integer number (1256877000).

Almost surely, 210033302113 is an apocalyptic number.

It is an amenable number.

10033302113 is a deficient number, since it is larger than the sum of its proper divisors (21713887).

10033302113 is an equidigital number, since it uses as much as digits as its factorization.

10033302113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8871.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 10033302113 its reverse (31120333001), we get a palindrome (41153635114).

The spelling of 10033302113 in words is "ten billion, thirty-three million, three hundred two thousand, one hundred thirteen".

Divisors: 1 599 3539 4733 2119861 2835067 16750087 10033302113