10033340115 has 16 divisors (see below), whose sum is σ = 16292947968. Its totient is φ = 5271246816.

The previous prime is 10033340077. The next prime is 10033340131. The reversal of 10033340115 is 51104333001.

It is not a de Polignac number, because 10033340115 - 2³¹ = 7885856467 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10033340091 and 10033340100.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4990707 + ... + 4992716.

It is an arithmetic number, because the mean of its divisors is an integer number (1018309248).

Almost surely, 2^10033340115 is an apocalyptic number.

10033340115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

10033340115 is a deficient number, since it is larger than the sum of its proper divisors (6259607853).

10033340115 is an equidigital number, since it uses as much as digits as its factorization.

10033340115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9983498.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 10033340115 its reverse (51104333001), we get a palindrome (61137673116).

The spelling of 10033340115 in words is "ten billion, thirty-three million, three hundred forty thousand, one hundred fifteen".