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10038162433 = 131013762257
BaseRepresentation
bin10010101100101001…
…00011010000000001
3221220120120111010211
421112110203100001
5131024232144213
64340024354121
7503516654455
oct112624432001
927816514124
1010038162433
114291310012
121b41915941
13c3c88c7b0
146b3258665
153db3ea53d
hex256523401

10038162433 has 8 divisors (see below), whose sum is σ = 10821014568. Its totient is φ = 9256836864.

The previous prime is 10038162427. The next prime is 10038162437. The reversal of 10038162433 is 33426183001.

It can be written as a sum of positive squares in 4 ways, for example, as 2418967489 + 7619194944 = 49183^2 + 87288^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10038162433 - 25 = 10038162401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10038162395 and 10038162404.

It is not an unprimeable number, because it can be changed into a prime (10038162437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 367960 + ... + 394297.

It is an arithmetic number, because the mean of its divisors is an integer number (1352626821).

Almost surely, 210038162433 is an apocalyptic number.

10038162433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10038162433 is a deficient number, since it is larger than the sum of its proper divisors (782852135).

10038162433 is a wasteful number, since it uses less digits than its factorization.

10038162433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 763283.

The product of its (nonzero) digits is 10368, while the sum is 31.

The spelling of 10038162433 in words is "ten billion, thirty-eight million, one hundred sixty-two thousand, four hundred thirty-three".

Divisors: 1 13 1013 13169 762257 9909341 772166341 10038162433