100401311433 has 4 divisors (see below), whose sum is σ = 133868415248. Its totient is φ = 66934207620.

The previous prime is 100401311383. The next prime is 100401311497. The reversal of 100401311433 is 334113104001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 100401311433 - 2¹³ = 100401303241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100401311233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16733551903 + ... + 16733551908.

It is an arithmetic number, because the mean of its divisors is an integer number (33467103812).

Almost surely, 2^100401311433 is an apocalyptic number.

It is an amenable number.

100401311433 is a deficient number, since it is larger than the sum of its proper divisors (33467103815).

100401311433 is an equidigital number, since it uses as much as digits as its factorization.

100401311433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33467103814.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 100401311433 its reverse (334113104001), we get a palindrome (434514415434).

The spelling of 100401311433 in words is "one hundred billion, four hundred one million, three hundred eleven thousand, four hundred thirty-three".