10040135421235 has 8 divisors (see below), whose sum is σ = 12682276321680. Its totient is φ = 7609365792864.

The previous prime is 10040135421223. The next prime is 10040135421241. The reversal of 10040135421235 is 53212453104001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10040135421235 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10040135421197 and 10040135421206.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52842817912 + ... + 52842818101.

It is an arithmetic number, because the mean of its divisors is an integer number (1585284540210).

Almost surely, 2^{10040135421235} is an apocalyptic number.

10040135421235 is a deficient number, since it is larger than the sum of its proper divisors (2642140900445).

10040135421235 is a wasteful number, since it uses less digits than its factorization.

10040135421235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105685636037.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 10040135421235 its reverse (53212453104001), we get a palindrome (63252588525236).

The spelling of 10040135421235 in words is "ten trillion, forty billion, one hundred thirty-five million, four hundred twenty-one thousand, two hundred thirty-five".