100402012420033 has 4 divisors (see below), whose sum is σ = 100402185174148. Its totient is φ = 100401839665920.

The previous prime is 100402012420007. The next prime is 100402012420091. The reversal of 100402012420033 is 330024210204001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 16612740712129 + 83789271707904 = 4075873^2 + 9153648^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100402012420033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100402012419986 and 100402012420013.

It is not an unprimeable number, because it can be changed into a prime (100402012423033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85502328 + ... + 86668633.

It is an arithmetic number, because the mean of its divisors is an integer number (25100546293537).

Almost surely, 2^{100402012420033} is an apocalyptic number.

It is an amenable number.

100402012420033 is a deficient number, since it is larger than the sum of its proper divisors (172754115).

100402012420033 is an equidigital number, since it uses as much as digits as its factorization.

100402012420033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 172754114.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 100402012420033 its reverse (330024210204001), we get a palindrome (430426222624034).

The spelling of 100402012420033 in words is "one hundred trillion, four hundred two billion, twelve million, four hundred twenty thousand, thirty-three".