100403141331 has 8 divisors (see below), whose sum is σ = 134159994880. Its totient is φ = 66790857672.

The previous prime is 100403141309. The next prime is 100403141339. The reversal of 100403141331 is 133141304001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100403141331 - 2⁵ = 100403141299 is a prime.

It is a super-2 number, since 2×100403141331² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100403141298 and 100403141307.

It is not an unprimeable number, because it can be changed into a prime (100403141339) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36140851 + ... + 36143628.

It is an arithmetic number, because the mean of its divisors is an integer number (16769999360).

Almost surely, 2^100403141331 is an apocalyptic number.

100403141331 is a deficient number, since it is larger than the sum of its proper divisors (33756853549).

100403141331 is an equidigital number, since it uses as much as digits as its factorization.

100403141331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72284945.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 100403141331 its reverse (133141304001), we get a palindrome (233544445332).

The spelling of 100403141331 in words is "one hundred billion, four hundred three million, one hundred forty-one thousand, three hundred thirty-one".