100403212433 has 8 divisors (see below), whose sum is σ = 100490458152. Its totient is φ = 100316002176.

The previous prime is 100403212421. The next prime is 100403212501. The reversal of 100403212433 is 334212304001.

It can be written as a sum of positive squares in 4 ways, for example, as 274001809 + 100129210624 = 16553^2 + 316432^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100403212433 - 2⁶ = 100403212369 is a prime.

It is a super-2 number, since 2×100403212433² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 100403212399 and 100403212408.

It is not an unprimeable number, because it can be changed into a prime (100403212333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9998291 + ... + 10008327.

It is an arithmetic number, because the mean of its divisors is an integer number (12561307269).

Almost surely, 2^100403212433 is an apocalyptic number.

It is an amenable number.

100403212433 is a deficient number, since it is larger than the sum of its proper divisors (87245719).

100403212433 is a wasteful number, since it uses less digits than its factorization.

100403212433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17731.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 100403212433 its reverse (334212304001), we get a palindrome (434615516434).

The spelling of 100403212433 in words is "one hundred billion, four hundred three million, two hundred twelve thousand, four hundred thirty-three".