10040401312041 has 4 divisors (see below), whose sum is σ = 13387201749392. Its totient is φ = 6693600874692.

The previous prime is 10040401312009. The next prime is 10040401312127. The reversal of 10040401312041 is 14021310404001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10040401312041 - 2⁵ = 10040401312009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10040401311999 and 10040401312017.

It is not an unprimeable number, because it can be changed into a prime (10040401312001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1673400218671 + ... + 1673400218676.

It is an arithmetic number, because the mean of its divisors is an integer number (3346800437348).

Almost surely, 2^{10040401312041} is an apocalyptic number.

It is an amenable number.

10040401312041 is a deficient number, since it is larger than the sum of its proper divisors (3346800437351).

10040401312041 is an equidigital number, since it uses as much as digits as its factorization.

10040401312041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3346800437350.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 10040401312041 its reverse (14021310404001), we get a palindrome (24061711716042).

The spelling of 10040401312041 in words is "ten trillion, forty billion, four hundred one million, three hundred twelve thousand, forty-one".