100409932682113 has 4 divisors (see below), whose sum is σ = 103872344153940. Its totient is φ = 96947521210288.

The previous prime is 100409932682077. The next prime is 100409932682131. The reversal of 100409932682113 is 311286239904001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 32449166637889 + 67960766044224 = 5696417^2 + 8243832^2 .

It is a cyclic number.

It is not a de Polignac number, because 100409932682113 - 2²⁹ = 100409395811201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100409932682153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1731205735870 + ... + 1731205735927.

It is an arithmetic number, because the mean of its divisors is an integer number (25968086038485).

Almost surely, 2^{100409932682113} is an apocalyptic number.

It is an amenable number.

100409932682113 is a deficient number, since it is larger than the sum of its proper divisors (3462411471827).

100409932682113 is an equidigital number, since it uses as much as digits as its factorization.

100409932682113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3462411471826.

The product of its (nonzero) digits is 559872, while the sum is 49.

The spelling of 100409932682113 in words is "one hundred trillion, four hundred nine billion, nine hundred thirty-two million, six hundred eighty-two thousand, one hundred thirteen".