10041134040131 has 4 divisors (see below), whose sum is σ = 10067351100672. Its totient is φ = 10014916979592.

The previous prime is 10041134040079. The next prime is 10041134040143. The reversal of 10041134040131 is 13104043114001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10041134040131 - 2¹⁰ = 10041134039107 is a prime.

It is a super-2 number, since 2×10041134040131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10041134040097 and 10041134040106.

It is not an unprimeable number, because it can be changed into a prime (10041134046131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13108529696 + ... + 13108530461.

It is an arithmetic number, because the mean of its divisors is an integer number (2516837775168).

Almost surely, 2^{10041134040131} is an apocalyptic number.

10041134040131 is a deficient number, since it is larger than the sum of its proper divisors (26217060541).

10041134040131 is an equidigital number, since it uses as much as digits as its factorization.

10041134040131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26217060540.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 10041134040131 its reverse (13104043114001), we get a palindrome (23145177154132).

The spelling of 10041134040131 in words is "ten trillion, forty-one billion, one hundred thirty-four million, forty thousand, one hundred thirty-one".