10041314254633 has 4 divisors (see below), whose sum is σ = 10387566470340. Its totient is φ = 9695062038928.

The previous prime is 10041314254597. The next prime is 10041314254637. The reversal of 10041314254633 is 33645241314001.

10041314254633 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5196266139024 + 4845048115609 = 2279532^2 + 2201147^2 .

It is a cyclic number.

It is not a de Polignac number, because 10041314254633 - 2³⁷ = 9903875301161 is a prime.

It is a super-3 number, since 3×10041314254633³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10041314254592 and 10041314254601.

It is not an unprimeable number, because it can be changed into a prime (10041314254637) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 173126107810 + ... + 173126107867.

It is an arithmetic number, because the mean of its divisors is an integer number (2596891617585).

Almost surely, 2^{10041314254633} is an apocalyptic number.

It is an amenable number.

10041314254633 is a deficient number, since it is larger than the sum of its proper divisors (346252215707).

10041314254633 is an equidigital number, since it uses as much as digits as its factorization.

10041314254633 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 346252215706.

The product of its (nonzero) digits is 103680, while the sum is 37.

Adding to 10041314254633 its reverse (33645241314001), we get a palindrome (43686555568634).

The spelling of 10041314254633 in words is "ten trillion, forty-one billion, three hundred fourteen million, two hundred fifty-four thousand, six hundred thirty-three".