Base | Representation |
---|---|
bin | 10010101101000001… |
… | …01001000100100001 |
3 | 221220210112111222020 |
4 | 21112200221010201 |
5 | 131031040111001 |
6 | 4340220332053 |
7 | 503555625261 |
oct | 112640510441 |
9 | 27823474866 |
10 | 10041332001 |
11 | 4293085398 |
12 | 1b429a4029 |
13 | c4042c38c |
14 | 6b38417a1 |
15 | 3db824736 |
hex | 256829121 |
10041332001 has 8 divisors (see below), whose sum is σ = 13391033760. Its totient is φ = 6692925792.
The previous prime is 10041331999. The next prime is 10041332027. The reversal of 10041332001 is 10023314001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 10041332001 - 21 = 10041331999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (10041332201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 305655 + ... + 336908.
It is an arithmetic number, because the mean of its divisors is an integer number (1673879220).
Almost surely, 210041332001 is an apocalyptic number.
It is an amenable number.
10041332001 is a deficient number, since it is larger than the sum of its proper divisors (3349701759).
10041332001 is an equidigital number, since it uses as much as digits as its factorization.
10041332001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 647775.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 10041332001 its reverse (10023314001), we get a palindrome (20064646002).
The spelling of 10041332001 in words is "ten billion, forty-one million, three hundred thirty-two thousand, one".
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