1004140111433 has 4 divisors (see below), whose sum is σ = 1004757285840. Its totient is φ = 1003522937028.

The previous prime is 1004140111427. The next prime is 1004140111451. The reversal of 1004140111433 is 3341110414001.

1004140111433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1004140111433 - 2⁴ = 1004140111417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1004140111399 and 1004140111408.

It is not an unprimeable number, because it can be changed into a prime (1004140111423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 308584763 + ... + 308588016.

It is an arithmetic number, because the mean of its divisors is an integer number (251189321460).

Almost surely, 2^{1004140111433} is an apocalyptic number.

It is an amenable number.

1004140111433 is a deficient number, since it is larger than the sum of its proper divisors (617174407).

1004140111433 is an equidigital number, since it uses as much as digits as its factorization.

1004140111433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 617174406.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1004140111433 its reverse (3341110414001), we get a palindrome (4345250525434).

The spelling of 1004140111433 in words is "one trillion, four billion, one hundred forty million, one hundred eleven thousand, four hundred thirty-three".