10041421400131 has 4 divisors (see below), whose sum is σ = 10954277891064. Its totient is φ = 9128564909200.

The previous prime is 10041421400093. The next prime is 10041421400161. The reversal of 10041421400131 is 13100412414001.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-10041421400131 is a prime.

It is a super-3 number, since 3×10041421400131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10041421400161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 456428245450 + ... + 456428245471.

It is an arithmetic number, because the mean of its divisors is an integer number (2738569472766).

Almost surely, 2^{10041421400131} is an apocalyptic number.

10041421400131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

10041421400131 is a deficient number, since it is larger than the sum of its proper divisors (912856490933).

10041421400131 is an equidigital number, since it uses as much as digits as its factorization.

10041421400131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 912856490932.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 10041421400131 its reverse (13100412414001), we get a palindrome (23141833814132).

The spelling of 10041421400131 in words is "ten trillion, forty-one billion, four hundred twenty-one million, four hundred thousand, one hundred thirty-one".