10042541315041 has 4 divisors (see below), whose sum is σ = 10042550064900. Its totient is φ = 10042532565184.

The previous prime is 10042541314997. The next prime is 10042541315099. The reversal of 10042541315041 is 14051314524001.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 7377416499600 + 2665124815441 = 2716140^2 + 1632521^2 .

It is a cyclic number.

It is not a de Polignac number, because 10042541315041 - 2⁹ = 10042541314529 is a prime.

It is a super-3 number, since 3×10042541315041³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10042541314994 and 10042541315012.

It is not an unprimeable number, because it can be changed into a prime (10042541315141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2336836 + ... + 5054293.

It is an arithmetic number, because the mean of its divisors is an integer number (2510637516225).

Almost surely, 2^{10042541315041} is an apocalyptic number.

It is an amenable number.

10042541315041 is a deficient number, since it is larger than the sum of its proper divisors (8749859).

10042541315041 is an equidigital number, since it uses as much as digits as its factorization.

10042541315041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8749858.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 10042541315041 its reverse (14051314524001), we get a palindrome (24093855839042).

The spelling of 10042541315041 in words is "ten trillion, forty-two billion, five hundred forty-one million, three hundred fifteen thousand, forty-one".