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100430245433 = 714347177919
BaseRepresentation
bin101110110001000011…
…0111110111000111001
3100121020011020002000202
41131202012332320321
53121140120323213
6114045332411545
710153520000240
oct1354206767071
9317204202022
10100430245433
1139657289941
1217569a76bb5
1396169b093b
144c0a259957
15292bdc4b58
hex17621bee39

100430245433 has 4 divisors (see below), whose sum is σ = 114777423360. Its totient is φ = 86083067508.

The previous prime is 100430245427. The next prime is 100430245441. The reversal of 100430245433 is 334542034001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100430245433 - 24 = 100430245417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100430245396 and 100430245405.

It is not an unprimeable number, because it can be changed into a prime (100430245933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7173588953 + ... + 7173588966.

It is an arithmetic number, because the mean of its divisors is an integer number (28694355840).

Almost surely, 2100430245433 is an apocalyptic number.

It is an amenable number.

100430245433 is a deficient number, since it is larger than the sum of its proper divisors (14347177927).

100430245433 is an equidigital number, since it uses as much as digits as its factorization.

100430245433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14347177926.

The product of its (nonzero) digits is 17280, while the sum is 29.

Adding to 100430245433 its reverse (334542034001), we get a palindrome (434972279434).

The spelling of 100430245433 in words is "one hundred billion, four hundred thirty million, two hundred forty-five thousand, four hundred thirty-three".

Divisors: 1 7 14347177919 100430245433