Base | Representation |
---|---|
bin | 10010101101001111… |
… | …00000011000101001 |
3 | 221220220220221022212 |
4 | 21112213200120221 |
5 | 131032020201213 |
6 | 4340323054505 |
7 | 503610131366 |
oct | 112647403051 |
9 | 27826827285 |
10 | 10043131433 |
11 | 42940a4325 |
12 | 1b43511435 |
13 | c4090c42a |
14 | 6b3b8d46d |
15 | 3dba7c9a8 |
hex | 2569e0629 |
10043131433 has 4 divisors (see below), whose sum is σ = 10389446340. Its totient is φ = 9696816528.
The previous prime is 10043131421. The next prime is 10043131477. The reversal of 10043131433 is 33413134001.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2207872144 + 7835259289 = 46988^2 + 88517^2 .
It is a cyclic number.
It is not a de Polignac number, because 10043131433 - 28 = 10043131177 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10043131399 and 10043131408.
It is not an unprimeable number, because it can be changed into a prime (10043131333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 173157410 + ... + 173157467.
It is an arithmetic number, because the mean of its divisors is an integer number (2597361585).
Almost surely, 210043131433 is an apocalyptic number.
It is an amenable number.
10043131433 is a deficient number, since it is larger than the sum of its proper divisors (346314907).
10043131433 is an equidigital number, since it uses as much as digits as its factorization.
10043131433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 346314906.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 10043131433 its reverse (33413134001), we get a palindrome (43456265434).
The spelling of 10043131433 in words is "ten billion, forty-three million, one hundred thirty-one thousand, four hundred thirty-three".
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