10043141131 has 4 divisors (see below), whose sum is σ = 10043814064. Its totient is φ = 10042468200.

The previous prime is 10043141123. The next prime is 10043141149. The reversal of 10043141131 is 13114134001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10043141131 - 2³ = 10043141123 is a prime.

It is a super-2 number, since 2×10043141131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10043141099 and 10043141108.

It is not an unprimeable number, because it can be changed into a prime (10043141191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 313560 + ... + 344101.

It is an arithmetic number, because the mean of its divisors is an integer number (2510953516).

Almost surely, 2^10043141131 is an apocalyptic number.

10043141131 is a deficient number, since it is larger than the sum of its proper divisors (672933).

10043141131 is an equidigital number, since it uses as much as digits as its factorization.

10043141131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 672932.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10043141131 its reverse (13114134001), we get a palindrome (23157275132).

The spelling of 10043141131 in words is "ten billion, forty-three million, one hundred forty-one thousand, one hundred thirty-one".