Base | Representation |
---|---|
bin | 1001001000100110010000… |
… | …1100100001101111000011 |
3 | 1022120010112212012001022021 |
4 | 2102021210030201233003 |
5 | 2304022202010343210 |
6 | 33205500210022311 |
7 | 2054414461032346 |
oct | 222114414415703 |
9 | 38503485161267 |
10 | 10043314543555 |
11 | 322238925a757 |
12 | 1162565877997 |
13 | 57b107b12a57 |
14 | 26a1559c045d |
15 | 1263b2901bda |
hex | 92264321bc3 |
10043314543555 has 16 divisors (see below), whose sum is σ = 12118795704288. Its totient is φ = 7990107840000.
The previous prime is 10043314543547. The next prime is 10043314543579. The reversal of 10043314543555 is 55534541334001.
It is not a de Polignac number, because 10043314543555 - 23 = 10043314543547 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 81823980 + ... + 81946630.
It is an arithmetic number, because the mean of its divisors is an integer number (757424731518).
Almost surely, 210043314543555 is an apocalyptic number.
10043314543555 is a deficient number, since it is larger than the sum of its proper divisors (2075481160733).
10043314543555 is a wasteful number, since it uses less digits than its factorization.
10043314543555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 213318.
The product of its (nonzero) digits is 1080000, while the sum is 43.
Adding to 10043314543555 its reverse (55534541334001), we get a palindrome (65577855877556).
The spelling of 10043314543555 in words is "ten trillion, forty-three billion, three hundred fourteen million, five hundred forty-three thousand, five hundred fifty-five".
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