100433401321 has 4 divisors (see below), whose sum is σ = 109563710544. Its totient is φ = 91303092100.

The previous prime is 100433401307. The next prime is 100433401337. The reversal of 100433401321 is 123104334001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 100433401321 - 2¹³ = 100433393129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100433401292 and 100433401301.

It is not an unprimeable number, because it can be changed into a prime (100434401321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4565154595 + ... + 4565154616.

It is an arithmetic number, because the mean of its divisors is an integer number (27390927636).

Almost surely, 2^100433401321 is an apocalyptic number.

100433401321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

100433401321 is a deficient number, since it is larger than the sum of its proper divisors (9130309223).

100433401321 is an equidigital number, since it uses as much as digits as its factorization.

100433401321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9130309222.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 100433401321 its reverse (123104334001), we get a palindrome (223537735322).

The spelling of 100433401321 in words is "one hundred billion, four hundred thirty-three million, four hundred one thousand, three hundred twenty-one".