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100444414131 = 3211160490459
BaseRepresentation
bin101110110001011110…
…1000010000010110011
3100121021010212220211100
41131202331002002303
53121202232223011
6114051000215443
710154051301345
oct1354275020263
9317233786740
10100444414131
1139664287006
121757276a583
139619901a99
144c0c0a7295
15292d272d56
hex1762f420b3

100444414131 has 6 divisors (see below), whose sum is σ = 145086375980. Its totient is φ = 66962942748.

The previous prime is 100444414129. The next prime is 100444414151. The reversal of 100444414131 is 131414444001.

It is not a de Polignac number, because 100444414131 - 21 = 100444414129 is a prime.

It is a super-2 number, since 2×1004444141312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100444414095 and 100444414104.

It is not an unprimeable number, because it can be changed into a prime (100444414151) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5580245221 + ... + 5580245238.

Almost surely, 2100444414131 is an apocalyptic number.

100444414131 is a deficient number, since it is larger than the sum of its proper divisors (44641961849).

100444414131 is a wasteful number, since it uses less digits than its factorization.

100444414131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11160490465 (or 11160490462 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 27.

Adding to 100444414131 its reverse (131414444001), we get a palindrome (231858858132).

The spelling of 100444414131 in words is "one hundred billion, four hundred forty-four million, four hundred fourteen thousand, one hundred thirty-one".

Divisors: 1 3 9 11160490459 33481471377 100444414131