Base | Representation |
---|---|
bin | 10110110110010000010001… |
… | …101101100101111010010011 |
3 | 111011210022020221202211202121 |
4 | 112312100101231211322103 |
5 | 101132323000104143101 |
6 | 553414200004555111 |
7 | 30110553461226442 |
oct | 2666202155457223 |
9 | 434708227684677 |
10 | 100485352021651 |
11 | 2a021664628743 |
12 | b32a8990b2a97 |
13 | 440b96065b0bc |
14 | 1ab5734886d59 |
15 | b93cc44760a1 |
hex | 5b6411b65e93 |
100485352021651 has 4 divisors (see below), whose sum is σ = 102188493581400. Its totient is φ = 98782210461904.
The previous prime is 100485352021631. The next prime is 100485352021667. The reversal of 100485352021651 is 156120253584001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100485352021651 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100485352021598 and 100485352021607.
It is not an unprimeable number, because it can be changed into a prime (100485352021631) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 851570779786 + ... + 851570779903.
It is an arithmetic number, because the mean of its divisors is an integer number (25547123395350).
Almost surely, 2100485352021651 is an apocalyptic number.
100485352021651 is a deficient number, since it is larger than the sum of its proper divisors (1703141559749).
100485352021651 is an equidigital number, since it uses as much as digits as its factorization.
100485352021651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1703141559748.
The product of its (nonzero) digits is 288000, while the sum is 43.
The spelling of 100485352021651 in words is "one hundred trillion, four hundred eighty-five billion, three hundred fifty-two million, twenty-one thousand, six hundred fifty-one".
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