Base | Representation |
---|---|
bin | 10010101101111110… |
… | …10000010000000001 |
3 | 221221100122012221001 |
4 | 21112333100100001 |
5 | 131040113404201 |
6 | 4341104332001 |
7 | 504014060221 |
oct | 112677202001 |
9 | 27840565831 |
10 | 10049356801 |
11 | 4297666560 |
12 | 1b45614001 |
13 | c41cabb93 |
14 | 6b4930081 |
15 | 3dc3ac301 |
hex | 256fd0401 |
10049356801 has 4 divisors (see below), whose sum is σ = 10962934704. Its totient is φ = 9135778900.
The previous prime is 10049356789. The next prime is 10049356907. The reversal of 10049356801 is 10865394001.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10049356801 is a prime.
It is a super-2 number, since 2×100493568012 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10049356501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 456788935 + ... + 456788956.
It is an arithmetic number, because the mean of its divisors is an integer number (2740733676).
Almost surely, 210049356801 is an apocalyptic number.
10049356801 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
10049356801 is a deficient number, since it is larger than the sum of its proper divisors (913577903).
10049356801 is an equidigital number, since it uses as much as digits as its factorization.
10049356801 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 913577902.
The product of its (nonzero) digits is 25920, while the sum is 37.
The spelling of 10049356801 in words is "ten billion, forty-nine million, three hundred fifty-six thousand, eight hundred one".
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