100499952112801 has 4 divisors (see below), whose sum is σ = 100500084304432. Its totient is φ = 100499819921172.

The previous prime is 100499952112771. The next prime is 100499952112873. The reversal of 100499952112801 is 108211259994001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100499952112801 is a prime.

It is a super-4 number, since 4×100499952112801⁴ (a number of 57 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100499952112891) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64948791 + ... + 66478156.

It is an arithmetic number, because the mean of its divisors is an integer number (25125021076108).

Almost surely, 2^{100499952112801} is an apocalyptic number.

It is an amenable number.

100499952112801 is a deficient number, since it is larger than the sum of its proper divisors (132191631).

100499952112801 is an equidigital number, since it uses as much as digits as its factorization.

100499952112801 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132191630.

The product of its (nonzero) digits is 466560, while the sum is 52.

The spelling of 100499952112801 in words is "one hundred trillion, four hundred ninety-nine billion, nine hundred fifty-two million, one hundred twelve thousand, eight hundred one".