Base | Representation |
---|---|
bin | 11101010000001110001… |
… | …01001100101101011011 |
3 | 10120002110000101221012120 |
4 | 32220013011030231123 |
5 | 112432012113304210 |
6 | 2045431103112323 |
7 | 132422222545113 |
oct | 16500705145533 |
9 | 3502400357176 |
10 | 1005141150555 |
11 | 358306a80453 |
12 | 1429778a26a3 |
13 | 73a27448369 |
14 | 3691316c043 |
15 | 1b22cca0270 |
hex | ea0714cb5b |
1005141150555 has 8 divisors (see below), whose sum is σ = 1608225840912. Its totient is φ = 536075280288.
The previous prime is 1005141150539. The next prime is 1005141150593. The reversal of 1005141150555 is 5550511415001.
1005141150555 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1005141150555 - 24 = 1005141150539 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33504705004 + ... + 33504705033.
It is an arithmetic number, because the mean of its divisors is an integer number (201028230114).
Almost surely, 21005141150555 is an apocalyptic number.
1005141150555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1005141150555 is a deficient number, since it is larger than the sum of its proper divisors (603084690357).
1005141150555 is an equidigital number, since it uses as much as digits as its factorization.
1005141150555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67009410045.
The product of its (nonzero) digits is 12500, while the sum is 33.
Adding to 1005141150555 its reverse (5550511415001), we get a palindrome (6555652565556).
The spelling of 1005141150555 in words is "one trillion, five billion, one hundred forty-one million, one hundred fifty thousand, five hundred fifty-five".
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